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50 mL of 0.10 M HCl is mixed with 50 mL of 0.20 M NaOH at 298 K.…

Question

50 mL of 0.10 M HCl is mixed with 50 mL of 0.20 M NaOH at 298 K. Assuming both are strong electrolytes and volumes are additive, calculate the pH of the resulting solution. Give the answer rounded to three decimal places.

✓ Verified answer: 12.699checked by our engine — not a guess

Step-by-step solution

Millimoles HCl = 0.10*50 = 5.0; millimoles NaOH = 0.20*50 = 10.0.
After neutralization, excess OH- = 10.0 - 5.0 = 5.0 mmol in total volume 100 mL.
[OH-] = 5.0/100 = 0.050 M.
pOH = -log10(0.050) = 1.301.
pH = 14 - 1.301 = 12.699.

Final answer12.699

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