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For the equilibrium N2(g) + 3H2(g) <=> 2NH3(g), the partial pressures…
Question
For the equilibrium N2(g) + 3H2(g) <=> 2NH3(g), the partial pressures at equilibrium are found to be p(NH3) = 0.40 atm, p(N2) = 0.30 atm and p(H2) = 0.60 atm. Calculate Kp (in atm^-2) for the reaction. Give the answer rounded to four decimal places.
✓ Verified answer: 2.4691checked by our engine — not a guess
Step-by-step solution
Kp = p(NH3)^2 / [p(N2) * p(H2)^3] = (0.40)^2 / [0.30 * (0.60)^3] = 0.16 / [0.30 * 0.216] = 0.16 / 0.0648 = 2.4691 atm^-2. Final answer: 2.4691
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