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For the reaction H2(g) + I2(g) <=> 2HI(g), Kc = 64 at the given…

Question

For the reaction H2(g) + I2(g) <=> 2HI(g), Kc = 64 at the given temperature. Starting with 1.0 mol H2 and 1.0 mol I2 in a closed vessel (same volume), calculate the number of moles of HI present at equilibrium. Give the answer rounded to three decimal places.

✓ Verified answer: 1.6checked by our engine — not a guess

Step-by-step solution

Let x mol each of H2 and I2 react.

At equilibrium: H2 = 1-x, I2 = 1-x, HI = 2x.
Since volume cancels, Kc = (2x)^2/[(1-x)(1-x)] = 64.
Taking square root: 2x/(1-x) = 8, so 2x = 8 - 8x, 10x = 8, x = 0.8.
Moles of HI = 2x = 1.6.

Final answer1.6

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