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Light of wavelength 600 nm passes through a single slit of width 0.2…
Question
Light of wavelength 600 nm passes through a single slit of width 0.2 mm and forms a diffraction pattern on a screen 2 m away. Find the width (in mm) of the central bright maximum.
✓ Verified answer: 12checked by our engine — not a guess
Step-by-step solution
The central maximum extends between the first minima on either side, at y = +/- lambda D/a.
Its full width = 2*lambda*D/a = 2*(600e-9)*(2)/(0.2e-3) = 2*600e-9*2/0.0002 = 0.012 m = 12 mm.
Final answer12
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