NEET + JEEAdvanced

A plano-convex lens is made of glass of refractive index 1.5; its…

Question

A plano-convex lens is made of glass of refractive index 1.5; its convex face has radius of curvature 20 cm and its flat face is silvered, turning the device into an equivalent mirror. Treating the system as a thin combination (light refracts through the lens, reflects at the silvered flat face, and refracts back through the lens), find the magnitude of the focal length (in cm) of this equivalent mirror.

✓ Verified answer: 20checked by our engine — not a guess

Step-by-step solution

Lens focal length: 1/f = (n-1)(1/R1 - 1/R2) = 0.5*(1/20) = 1/40, so f = 40 cm, power P_L = 1/40 D(cm).
The flat silvered face is a plane mirror, power P_m = 0.
Equivalent mirror power P = 2P_L + P_m = 2/40 = 1/20.
Equivalent focal length = 1/P = 20 cm.

Final answer20

Stuck on a problem like this?

Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.

Solve my doubt →

More Neet Optics Waves solutions