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A vibrating tuning fork held over a resonance tube produces its first…
Question
A vibrating tuning fork held over a resonance tube produces its first resonance when the air column length is 0.20 m and its second resonance at 0.62 m. Taking the speed of sound in air as 336 m/s, find the frequency of the tuning fork in Hz.
✓ Verified answer: 400checked by our engine — not a guess
Step-by-step solution
The difference between successive resonance lengths equals half a wavelength: l2 - l1 = lambda/2, so lambda = 2*(0.62 - 0.20) = 0.84 m.
Frequency f = v/lambda = 336/0.84 = 400 Hz.
(End correction cancels out in the difference method.) Final answer: 400
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