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A prism of refracting angle 60 degrees gives an angle of minimum…

Question

A prism of refracting angle 60 degrees gives an angle of minimum deviation of 30 degrees for a certain wavelength. For that wavelength, find the critical angle (in degrees) for total internal reflection at a glass-air interface of the same glass.

✓ Verified answer: 45checked by our engine — not a guess

Step-by-step solution

Refractive index from prism: n = sin((A+dmin)/2)/sin(A/2) = sin(45)/sin(30) = (1/sqrt2)/(1/2) = sqrt2 = 1.4142.
Critical angle C satisfies sin C = 1/n = 1/sqrt2, so C = 45 degrees.

Final answer45

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