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An electric dipole has dipole moment p = 2 x 10^-9 C·m. Find the…
Question
An electric dipole has dipole moment p = 2 x 10^-9 C·m. Find the magnitude of the electric field (in N/C) at a point located 0.30 m from the centre of the dipole, along a direction making 60 degrees with the dipole axis. Use k = 9 x 10^9 N·m^2/C^2 and the short-dipole approximation. Give the answer to three decimal places.
✓ Verified answer: 881.917checked by our engine — not a guess
Step-by-step solution
For a short dipole the field at distance r and polar angle theta is E = (kp/r^3) sqrt(1 + 3 cos^2 theta).
Here kp/r^3 = (9e9)(2e-9)/(0.3^3) = 18/0.027 = 666.667 N/C.
With theta = 60 deg, cos theta = 0.5, so sqrt(1 + 3(0.25)) = sqrt(1.75) = 1.32288.
Thus E = 666.667 x 1.32288 ≈ 881.917 N/C.
Final answer881.917
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