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A capacitor C1 = 4 microfarad is charged to 100 V and a capacitor C2…

Question

A capacitor C1 = 4 microfarad is charged to 100 V and a capacitor C2 = 6 microfarad is charged to 50 V. They are then connected in parallel with plates of like polarity joined together (positive to positive). Find the energy dissipated during the redistribution of charge, in microjoule.

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Step-by-step solution

Initial charges: Q1 = 4(100) = 400 uC, Q2 = 6(50) = 300 uC.

Like plates joined, so charges add: total Q = 700 uC on total capacitance 10 uF, giving common voltage Vc = 700/10 = 70 V.

Initial energy = 0.5(4)(100^2) + 0.5(6)(50^2) = 20000 + 7500 = 27500 uJ.
Final energy = 0.5(10)(70^2) = 24500 uJ.
Energy dissipated = 27500 - 24500 = 3000 uJ.

Final answer3000

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