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Two cells are connected in parallel and drive an external resistor.…
Question
Two cells are connected in parallel and drive an external resistor. Cell 1 has EMF 10 V and internal resistance 2 ohm; cell 2 has EMF 4 V and internal resistance 1 ohm; both have their positive terminals joined and connected across an external resistance R = 3 ohm. Find the current (in ampere) flowing through R, to three decimal places.
✓ Verified answer: 1.636checked by our engine — not a guess
Step-by-step solution
Let V be the common terminal voltage across R.
Node (junction) KCL with currents flowing in from each cell and out through R: (10-V)/2 + (4-V)/1 = V/3.
Multiply by 6: 3(10-V) + 6(4-V) = 2V, so 30 - 3V + 24 - 6V = 2V, i.e.
54 = 11V, V = 54/11.
Current through R = V/R = (54/11)/3 = 18/11 ≈ 1.636 A.
Final answer1.636
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