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For a reaction at 298 K, the standard Gibbs free energy change is…
Question
For a reaction at 298 K, the standard Gibbs free energy change is -13.6 kJ/mol. Using R = 8.314 J/mol/K, calculate the equilibrium constant K, rounded to 2 decimal places.
✓ Verified answer: 242.07checked by our engine — not a guess
Step-by-step solution
dG = -RT ln K, so K = exp(-dG/RT) = exp(13600/(8.314*298)) = exp(13600/2477.57) = exp(5.4894) = 242.07. Final answer: 242.07
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