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For the decomposition of a solid carbonate, the standard enthalpy…
Question
For the decomposition of a solid carbonate, the standard enthalpy change is +178.3 kJ per mole and the standard entropy change is +160.5 J per mole per kelvin, both assumed independent of temperature. Determine the temperature (in kelvin) above which the reaction becomes spontaneous, i.e. the temperature at which the standard Gibbs free energy change equals zero. Give your answer rounded to 2 decimal places.
✓ Verified answer: 1110.9checked by our engine — not a guess
Step-by-step solution
At the crossover temperature, dG = dH - T*dS = 0, so T = dH/dS. Convert dH to J: 178300 J/mol. T = 178300 / 160.5 = 1110.90 K. Final answer: 1110.9
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