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A gas mixture contains 2 moles of helium (monatomic) and 3 moles of…
Question
A gas mixture contains 2 moles of helium (monatomic) and 3 moles of oxygen (diatomic, treated with translational and rotational degrees of freedom only). Treating the mixture as one ideal gas, compute its adiabatic index gamma (ratio of specific heats), to four decimal places.
✓ Verified answer: 1.4762checked by our engine — not a guess
Step-by-step solution
Cv(He) = 3/2 R, Cv(O2) = 5/2 R.
Cv,mix = (n1*Cv1 + n2*Cv2)/(n1+n2) = (2*1.5 + 3*2.5)/5 = (3 + 7.5)/5 = 2.1 R.
Cp,mix = Cv,mix + R = 3.1 R.
gamma = 3.1/2.1 = 1.4762.
Final answer1.4762
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