NEET + JEEAdvanced
A hypothetical photoelectric experiment uses the same monochromatic…
Question
A hypothetical photoelectric experiment uses the same monochromatic light on a metal in two separate runs but the data are reported via stopping potentials only. When 400 nm light is used the stopping potential is 2.10 V, and when 620 nm light is used the stopping potential is 1.00 V. Assuming both data points obey the photoelectric equation with a single work function, determine the work function of the metal in eV.
✓ Verified answer: 1checked by our engine — not a guess
Step-by-step solution
Photoelectric: eVs = hc/lambda - phi. Subtracting the two equations eliminates phi:
Vs1 - Vs2 = hc(1/lambda1 - 1/lambda2).
hc = (2.10 - 1.00)/(1/400 - 1/620) = 1.10/(0.0025 - 0.0016129) = 1240 eV·nm.
Then phi = hc/lambda1 - Vs1 = 1240/400 - 2.10 = 3.10 - 2.10 = 1.00 eV.
Final answer1.0
Stuck on a problem like this?
Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.
Solve my doubt →More Neet Modern Thermo solutions
Light of a single wavelength falls on two different metal surfaces.…NEET + JEE · PhysicsIn a singly-ionized helium atom (He+, atomic number Z = 2) the…NEET + JEE · PhysicsFor the n = 2 stationary orbit of a hydrogen atom (Bohr radius a0 =…NEET + JEE · PhysicsA radioactive sample has an initial activity of 8000 disintegrations…NEET + JEE · PhysicsTwo deuterium nuclei fuse to form a helium-4 nucleus. Given atomic…NEET + JEE · PhysicsA Zener diode of breakdown voltage 6 V is used as a voltage…NEET + JEE · PhysicsAn n-p-n transistor in common-emitter configuration has a current…NEET + JEE · PhysicsAt what temperature (in kelvin) would the rms speed of oxygen…NEET + JEE · Physics