NEET + JEEAdvanced
A uniform solid sphere is released from rest at the top of a rough…
Question
A uniform solid sphere is released from rest at the top of a rough incline and rolls without slipping down the slope. By the time its centre has descended a vertical height of 1.75 m, find its speed (in m/s). Take g = 10 m/s^2 and use moment of inertia (2/5)MR^2 for a solid sphere.
✓ Verified answer: 5checked by our engine — not a guess
Step-by-step solution
For rolling without slipping, energy conservation gives m g h = (1/2) m v^2 + (1/2) I w^2 with I = (2/5)mR^2 and w = v/R.
So m g h = (1/2) m v^2 (1 + 2/5) = (7/10) m v^2.
Thus v^2 = (10/7) g h = (10/7)*10*1.75 = 25, giving v = 5 m/s.
Final answer5
Stuck on a problem like this?
Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.
Solve my doubt →More Neet Mechanics solutions
A projectile is launched from the foot of a fixed incline that rises…NEET + JEE · PhysicsOn a horizontal table, block A (2 kg) and block B (3 kg) rest in…NEET + JEE · PhysicsA ball of mass 0.5 kg is tied to a light string of length 2 m and…NEET + JEE · PhysicsA block starts from rest and slides down a smooth incline, descending…NEET + JEE · PhysicsA particle executes simple harmonic motion of period 12 s about a…NEET + JEE · PhysicsA satellite of mass 200 kg moves in a circular orbit around the Earth…NEET + JEE · PhysicsA bullet of mass 0.02 kg moving horizontally at 400 m/s strikes and…NEET + JEE · PhysicsCar B moves along a straight road at a constant 20 m/s. At the…NEET + JEE · Physics