NEET + JEEAdvanced
A ball of mass 0.5 kg is tied to a light string of length 2 m and…
Question
A ball of mass 0.5 kg is tied to a light string of length 2 m and whirled in a complete vertical circle. At the lowest point its speed is 12 m/s. Taking g = 10 m/s^2 and treating the string as inextensible, find the ratio of the string tension at the lowest point to the string tension at the highest point.
✓ Verified answer: 3.7273checked by our engine — not a guess
Step-by-step solution
Energy conservation between bottom and top (height 2L above bottom): v_top^2 = v_bottom^2 - 2g(2L) = 144 - 2*10*4 = 64 m^2/s^2.
At the lowest point: T_bottom = m v_b^2/L + mg = 0.5*144/2 + 0.5*10 = 36 + 5 = 41 N.
At the highest point: T_top = m v_t^2/L - mg = 0.5*64/2 - 5 = 16 - 5 = 11 N.
Ratio = 41/11 = 3.7273.
Final answer3.7273
Stuck on a problem like this?
Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.
Solve my doubt →More Neet Mechanics solutions
A projectile is launched from the foot of a fixed incline that rises…NEET + JEE · PhysicsOn a horizontal table, block A (2 kg) and block B (3 kg) rest in…NEET + JEE · PhysicsA block starts from rest and slides down a smooth incline, descending…NEET + JEE · PhysicsA uniform solid sphere is released from rest at the top of a rough…NEET + JEE · PhysicsA particle executes simple harmonic motion of period 12 s about a…NEET + JEE · PhysicsA satellite of mass 200 kg moves in a circular orbit around the Earth…NEET + JEE · PhysicsA bullet of mass 0.02 kg moving horizontally at 400 m/s strikes and…NEET + JEE · PhysicsCar B moves along a straight road at a constant 20 m/s. At the…NEET + JEE · Physics