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Let g(x) = x^2 + 250/x for x > 0. Find the minimum value of g(x).

Question

Let g(x) = x^2 + 250/x for x > 0. Find the minimum value of g(x).

✓ Verified answer: 75checked by our engine — not a guess

Step-by-step solution

Write g(x) = x^2 + 125/x + 125/x. By AM-GM on the three positive terms,
x^2 + 125/x + 125/x ≥ 3·(x^2 · 125/x · 125/x)^{1/3} = 3·(125·125)^{1/3} = 3·25 = 75.
Equality holds when x^2 = 125/x, i.e. x^3 = 125, x = 5. Then g(5) = 25 + 50 = 75.

Final answer75

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