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The cubic x^3 - a x^2 + (a - 1)x - 5 = 0 (with a a real parameter)…

Question

The cubic x^3 - a x^2 + (a - 1)x - 5 = 0 (with a a real parameter) has roots whose squares sum to 10. Determine the largest possible value of a.

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Step-by-step solution

Let the roots be r,s,t. Vieta gives r+s+t = a and rs+rt+st = a - 1. Then
r^2+s^2+t^2 = (r+s+t)^2 - 2(rs+rt+st) = a^2 - 2(a-1) = a^2 - 2a + 2.
Set this equal to 10: a^2 - 2a + 2 = 10, i.e. a^2 - 2a - 8 = 0, giving (a-4)(a+2)=0, so a = 4 or a = -2.
The largest value is a = 4.

Final answer4

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