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For a certain metal, monochromatic light of wavelength 200 nm…

Question

For a certain metal, monochromatic light of wavelength 200 nm produces a stopping potential of 4.2 V, and light of wavelength 400 nm produces a stopping potential of 1.1 V. Treat hc as an unknown constant to be determined from the data along with the work function. Find the threshold wavelength (longest wavelength that ejects photoelectrons) in nm.

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Step-by-step solution

Einstein's equation: eV_stop = hc/lambda - phi. Write two equations:
hc/200 - phi = 4.2 ... (1)
hc/400 - phi = 1.1 ... (2)
Subtract (2) from (1): hc(1/200 - 1/400) = 3.1, i.e.
hc*(1/400) = 3.1, so hc = 1240 eV*nm.
From (2): phi = 1240/400 - 1.1 = 3.1 - 1.1 = 2.0 eV.
Threshold wavelength lambda_0 = hc/phi = 1240/2.0 = 620 nm.

Final answer620

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