A uniform thin rod of mass 3 kg and length 2 m lies at rest on a…
Question
A uniform thin rod of mass 3 kg and length 2 m lies at rest on a frictionless horizontal table. A point particle of mass 1 kg, moving on the table with speed 8 m/s in a direction perpendicular to the rod, strikes one end of the rod and sticks to it. After the collision the combined body rotates with angular speed equal to p/q rad/s in lowest terms, where p and q are positive integers. Find p + q.
Step-by-step solution
After sticking, momentum and angular momentum are conserved (no external horizontal force/torque).
Locate the combined centre of mass: from the rod's centre it is d = m(L/2)/(M+m) = 1*(1)/4 = 0.25 m toward the impact end.
Final answer31
Stuck on a problem like this?
Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.
Solve my doubt →More Physics Mechanics solutions