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A mixture consists of 4.40 g of CO2 (molar mass 44) and 3.40 g of NH3…
Question
A mixture consists of 4.40 g of CO2 (molar mass 44) and 3.40 g of NH3 (molar mass 17). Using Avogadro's number 6.022 x 10^23 per mole, calculate the total number of atoms in the mixture, expressed in units of 10^23 (i.e. give the value N such that the total number of atoms = N x 10^23).
✓ Verified answer: 6.6242checked by our engine — not a guess
Step-by-step solution
Moles CO2 = 4.40/44 = 0.100; each CO2 has 3 atoms -> 0.300 mol atoms.
Moles NH3 = 3.40/17 = 0.200; each NH3 has 4 atoms -> 0.800 mol atoms.
Total mol of atoms = 0.300 + 0.800 = 1.100 mol.
Total atoms = 1.100 x 6.022e23 = 6.6242 x 10^23.
Final answer6.6242
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