NEET + JEEAdvanced
In a mass spectrometer, ions first pass through a velocity selector…
Question
In a mass spectrometer, ions first pass through a velocity selector with crossed fields: electric field 2.0 x 10^4 V/m and magnetic field 0.10 T. The selected ions (each of charge 1.6 x 10^-19 C) then enter a region of magnetic field 0.20 T perpendicular to their velocity and travel in a circular arc of radius 0.10 m. Find the mass of the ion in atomic mass units (1 u = 1.66 x 10^-27 kg).
✓ Verified answer: 9.638554checked by our engine — not a guess
Step-by-step solution
Velocity selector passes ions with v = E/B1 = 2.0e4/0.10 = 2.0e5 m/s.
In the analyzer, r = mv/(qB2), so m = q B2 r / v = (1.6e-19 x 0.20 x 0.10)/2.0e5 = 3.2e-21/2.0e5 = 1.6e-26 kg.
In u: 1.6e-26/1.66e-27 = 9.63855 u.
Final answer9.63855
Stuck on a problem like this?
Paste any JEE or NEET question — verified working, a confidence %, and an honest “not sure” instead of a bluff.
Solve my doubt →More Neet Magnetism Emi solutions
A cyclotron accelerates protons (mass 1.67 x 10^-27 kg, charge 1.6 x…NEET + JEE · PhysicsA charged particle with charge-to-mass ratio q/m = 1.0 x 10^8 C/kg…NEET + JEE · PhysicsTwo long straight parallel wires carry currents 10 A and 15 A in…NEET + JEE · PhysicsA square coil of side 0.10 m has 50 turns and carries a current of…NEET + JEE · PhysicsA conducting rod of length 0.50 m rotates in a horizontal plane about…NEET + JEE · PhysicsA long solenoid has 1000 turns per metre. A short secondary coil of…NEET + JEE · PhysicsA series LCR circuit has resistance 30 ohm, inductive reactance 50…NEET + JEE · PhysicsA charged particle with charge-to-mass ratio q/m = 5.0 x 10^7 C/kg…NEET + JEE · Physics