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In a mass spectrometer, ions first pass through a velocity selector…

Question

In a mass spectrometer, ions first pass through a velocity selector with crossed fields: electric field 2.0 x 10^4 V/m and magnetic field 0.10 T. The selected ions (each of charge 1.6 x 10^-19 C) then enter a region of magnetic field 0.20 T perpendicular to their velocity and travel in a circular arc of radius 0.10 m. Find the mass of the ion in atomic mass units (1 u = 1.66 x 10^-27 kg).

✓ Verified answer: 9.638554checked by our engine — not a guess

Step-by-step solution

Velocity selector passes ions with v = E/B1 = 2.0e4/0.10 = 2.0e5 m/s.
In the analyzer, r = mv/(qB2), so m = q B2 r / v = (1.6e-19 x 0.20 x 0.10)/2.0e5 = 3.2e-21/2.0e5 = 1.6e-26 kg.
In u: 1.6e-26/1.66e-27 = 9.63855 u.

Final answer9.63855

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