JEEOlympiad

Two players A and B take turns rolling a single fair six-sided die,…

Question

Two players A and B take turns rolling a single fair six-sided die, with A rolling first and then alternating. A wins instantly if A ever rolls a 6 on A's turn; B wins instantly if B ever rolls a 1 on B's turn. If a player does not roll the winning face on a turn, play passes to the opponent. Play continues until someone wins. Let the probability that A wins be m/n in lowest terms. Find m+n.

✓ Verified answer: 17checked by our engine — not a guess

Step-by-step solution

Let a = P(A ultimately wins | it is currently A's turn) and b = P(A ultimately wins | it is currently B's turn).

On A's turn: A rolls a 6 with prob 1/6 and wins (contributing 1); otherwise (prob 5/6) it becomes B's turn, contributing b. So

a = (1/6)(1) + (5/6) b.

On B's turn: B rolls a 1 with prob 1/6 and B wins (so A's winning prob is 0); otherwise (prob 5/6) it becomes A's turn, contributing a. So

b = (1/6)(0) + (5/6) a = (5/6) a.
Substitute: a = 1/6 + (5/6)(5/6)a = 1/6 + (25/36) a => a(1 - 25/36) = 1/6 => a(11/36) = 1/6 => a = (1/6)(36/11) = 6/11.
So P(A wins) = 6/11, m+n = 6+11 = 17.

Final answer17

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